CS/Math 166 Final Exam Postmortem -- Winter 2018

CS/Math 166 -- D. C. Smolarski, S.J.
Santa Clara University, Department of Mathematics and Computer Science

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Link to text of 2018 final exam (PDF file)

NOTES:

General:

As a matter of policy, I keep finals for one regular quarter. You may examine your final at any time in my office. If you wish to collect your final, you may do you in June.

Prob 1: (cf. Review page bullet 3,7; Notes 2-4)

Prob 2: (cf. Review page bullet 10; Notes 3-10, 3-11)

Prob 3: (cf. Review page bullet 24; Notes 4-26A)

Prob 4: (cf. Review page bullet 24)

Prob 5: (cf. Notes 6-27)

Prob 6: (cf. Review page bullet 26; Notes 4-26A)

Prob 7: (cf. Review page bullet 23; Notes 4-17)
I remember mentioning in class that "normal" equations are used in several ways in Numerical Analysis. This way is used to convert a non-symmetric system into a symmetric system.
Some people had the basic idea of using AT, but both sides of the original matrix-vector equation must be PRE-multiplied by the transpose. Some people POST-multiplied one side and PRE-multiplied the other side, but matrix multiplication is not commutative!
I distinctly remember mentioning in class about the "normal" equations for a linear system (not for approximating a curve through points) and mentioning the possibility of putting a question about "normal equations" on an exam in the past!

Prob 8: (cf. Review page bullet 47; Notes 6-14)
Some had problems doing the simple evaluation of the function (i.e., the polynomial within the integral) correctly at 2 or 3 points to get the Gauss Quad values. When n=3, some people evaluated f(0) to be 0, but it is 1. Both answers are the same as the analytic evaluation of the integral, which is 10/3 = 3.3333....

Prob 9: (cf. Review page bullet 46)
This problem specified that we wanted an exact formula for a polynomial of degree 0.
A polynomial of degree 0 is a constant. Thus f(x) can be taken out of the integral (on the left of the given equation) and "cancelled" with f(3/2) (which equals the same constant value) on the right. Then the left side of the initial equation can be evaluated exactly via the (integration by parts) formula given.
This was not intended so much as a "trick" question but as a question meant to see whether the reader took into account all the given information, which is very important in numerical problems.
A number of people tried to evaluate ln(3/2) which had nothing to do with the final value.
Some tried to create a quadrature formula with several points, but the only formula requested was the one with the single point (i.e., 3/2) and the single corresponding weight.

Prob 10: (cf. Review page bullet 48; Notes 6-18)
This was basically the same procedure that needed to be done for the Runge-Kutta programming assignment (MP 6). One introduces (two) new variables which eliminate some of the derivatives of y and then one creates several equations with a derivative on the left side and an expression with no derivatives on the right. Since you are given a 3rd order DiffEq (i.e., one with a 3rd derivative in it), you should end up with 3 first order DiffEqs (with a derivative on the left and an expression without derivatives on the right) and three (new) initial conditions related to new variables and based on the original variables and initial conditions.

Prob 11: (cf. Review bullet 43; Notes 6-8)
One needs to use the error formula to determinine the width needed and thus also the number of panels. A few people seemed to confuse the error formula for the Trapezoidal rule, which only has a 2nd derivative, with the correct formula for Simpson's rule. In the error formula the argument of f(4)(x) is chosen to maximize the value over the interval of integration. Thus x should be 3, since that where the 4th derivative is greatest on the interval given.
One should use the error formula for the "composite" version given in the notes.
Since Simpson's rule demands that n be an even number, the minimum answer was 32 (the next higher even number greater than 30.006).

Prob 12: (cf. Review page bullet 49; Notes 6-38A, 6-39)
Some had the correct discretization form for y'' but, unfortunately, made various algebraic errors (such as forgetting to correct for a minus sign inside parentheses) resulting in an incorrect final linear system.
A few used the discretized formula for the differential equation given in the notes as if it were a formula that could be used for any DiffEq.
Also, the question specifically asked for the linear system in "matrix form."

Prob 13: (cf. Review page bullet 44; Notes 6-11)
From information given in class, for the Trapezoidal rule, the value in the Richardson formula for the variable j in the exponent should be 2 since the increase in panels form the first value (5) to the second value (10). Thus the denominator of the fraction is 42-1-1 or 3. All one needed to do was insert the values given into the correct formula to produce a new value. Several used the correct formula but associated the given values incorrectly in the formula. When the number of panels goes from 5 to 10, the width of the panel is cut in half!

Prob 14: (cf. Review page bullet 41; Notes 6-4)
In each case, one was supposed to compute the approximation to the same integral over the same interval (0,1) but using various widths for the panels. When the width h is 1, then there is only one panel (since the distance between the two limits of the integral is 1) and only the two endpoints are used. When the width is 1/2, there are two panels and the two endpoints and the middle point is used. When the width is 1/4, all 5 points are used.
Some used all 5 points for each approximation or varied the interval final point depending on the panel widths. A few used the x value for one of the points rather than the y value.

Statistics

Scores, raw and normalized
  
      final   nfinal
      187     78
      177     72
      177     72
      171     69
      165     66
      165     66
      160     63
      154     60
      154     60
      153     60
      152     59
      152     59
      145     56
      142     54
      141     53
      138     52
      127     46
      122     44
      122     44
      122     44
      120     42
      120     42
      118     41
      118     41
      108     36
      107     36
      105     35
       83     23
       77     20
       49      5
      
MAXIMUM 200   100

Distribution


                            x
                       x    x
                       x    x    x
                  x    x    x    x
                  x    x    x    x
                  x    x    x    x
                  x    x    x    x
   x    x    x    x    x    x    x    x
   40-  60-  80- 100- 120- 140- 160- 180-
   59   79   99  119  139  159  179  200

  (1)  (1)  (1)  (5)  (7)  (8)  (6)  (1)

Number of Perfect Scores per Problem

  1. 16/30
  2. 16
  3. 9
  4. 8
  5. 12
  6. 21
  7. 11
  8. 19
  9. 11
  10. 9
  11. 4 "Hardest"
  12. 13
  13. 10
  14. 22 "Easiest"

This page is maintained by Dennis C. Smolarski, S.J. Email: dsmolarski "at" scu.edu
© Copyright 2018 Dennis C. Smolarski, SJ, All rights reserved.
Last changed: 21 March 2018